I have created a login form to a clothing website. I have used the isset() function with if statement on the button click saying if the button is clicked... do this.... But, when I run on browser(I use xammp as my localhost), the page works fine but when i enter the credentials and press submit button, it does not redirect to the next page or does not even echo"Login Successful" or "Login failed. I used error reporting function in php to track the bugs but it did not show any either. Here is my code
IndexLogin.html
<html lang="en">
<head>
<title>Login </title>
</head>
<body>
<div class="limiter">
<div class="container-login100">
<div class="wrap-login100">
<form class="login100-form validate-form">
<form method="POST" form action="login.php">
<span class="login100-form-title p-b-34">
SHAARANYA~<br>
Account Login
</span>
<div class="wrap-input100 rs1-wrap-input100 validate-input
m-b-20" data-validate="Type email">
<input id="email" class="input100" type="text"
name="email" placeholder="email" >
<span class="focus-input100"></span>
</div>
<div class="wrap-input100 rs2-wrap-input100 validate-input
m-b-20" data-validate="Type password">
<input class="input100" type="password" name="pass"
placeholder="Password" >
<span class="focus-input100"></span>
</div>
<div class="container-login100-form-btn">
<button class="login100-form-btn"
button type="submit" name="submit">
Sign in
</button>
</div>
<div class="w-full text-center p-t-27 p-b-239">
<span class="txt1">
Forgot
</span>
<a href="#" class="txt2">
User name / password?
</a>
<br>
<br>
<p><font size="3">Not a Member Yet? Join us for FREE!
<br><br><a href="#"><b> SIGN UP </font></b> </a></p>
</div>
</form>
</body>
</html>
Login.php
<?php
error_reporting(E_ALL);
ini_set('display_errors', '1');
$servername = "localhost";
$username = root;
$password = "";
$dbname="company";
$conn = new mysqli($servername,$username,$password,$dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if(isset($_POST['submit'])){
$email=$_POST['email'];
$pass=$_POST['pass'];
$sql = "SELECT * FROM login WHERE email = '".$email."' and pass =
'".$pass."'";
$result = mysqli_query( $conn,$sql);
if(mysql_num_rows($result)==1){
echo "Login Successful";
}
else {
echo "Failed To Login";
}
}
?>
