PHP /将数字作为字符串发布，intval无法将其转换为数字

Question

I'm grabbing a number using jquery, from a piece of data in my html, as follows.

This is the html line.

echo "<p class = 'bold center remainingland' data-RemainingLandForFacilities = $RemainingLandForFacilities>Remaining Land For New Facilities : " . ($RemainingLandForFacilities) . "</p>";

I get the data using jquery with this...

var remainingland = $(this).closest('div').find('.remainingland').attr('data-RemainingLandForFacilities');

(after pressing a button, which is 'this'). This works correctly and an alert shows me the number.

I then post to my php script with the usual...

$.post('scripts/upgradefacility.php',
            {
                remainingland : remainingland

And I collect it with.

$RemainingLand = filter_input(INPUT_POST, 'remainingland', FILTER_SANITIZE_STRING);

At this point, I do have the number, but it's a string (as confirmed by gettype). But when I try to convert it to an integer with...

$RemainingLand = intval($RemainingLand);

I just get a blank. I should point out that I just copy/pasted all of this from previous variables which I'm passing, all of which come through correctly, so this is really odd. I can only assume that I've made some error that I can't spot or that I've been doing something wrong all along but I've somehow got away with it until now.

Answer 1

Your problem isn't that intval() fails converting your data into an integer, your problem is you're returning it with exit().

exit() takes one argument. If it's an integer, rather than printing it out, it uses it as an exit status code.

More information on how exit() works can be found in the php documentation here:- http://php.net/manual/en/function.exit.php