如何根据当天循环列表？

Question

I have a simple XML list with dates inside (chronological order). I have found a way loop the list 7 times (1 week).

<?php
    $xmldata=simplexml_load_file("dates.xml");
    $i = 0;
    foreach($xmldata->day as $day) {
    if($i==7) break;
    $i++;
    echo "<p>Date: " . $day->date . "</p>";
    echo "<p>Dayname: " . $day->content . "</p>";
    }
    ?> 

Now I have the problem, that the loop always starts at the first line of the XML file and ends after 7 times. But I want to start the loop, when

 $xmldata->day->date = $currentday;
 $currentday = date('d.m.y');

and continue with the next 7 items (days) in the list.

The XML (dates.xml) looks like this:

<schedule>
  <day>
    <date>01.03.17</date>
    <information>Lorem ipsum</information>
  </day>
  <day>
    <date>02.03.17</date>
    <information>Lorem ipsum</information>
  </day>
  <day>
    <date>03.03.17</date>
    <information>Lorem ipsum</information>
  </day>
  ...
</schedule>

Thank you!

Answer 1

Solution after commnets:

<?php
$xmldata=simplexml_load_file("dates.xml");
$i = 0; 
$startfound = false;
foreach($xmldata->day as $day) {
    if(!$startfound && $day->date!=date('d.m.y')) continue;
    $startfound = true;
    if($i==7) break;
    $i++;
    echo "<p>Date: " . $day->date . "</p>";
    echo "<p>Dayname: " . $day->content . "</p>";
}
?>