php，按值排序数组（星期几）

Question

Is there a simple way to order this array (the days will always be displayed in right order)

  0 => "Thursday,Sunday"
  1 => "Tuesday"
  2 => "Monday"
  3 => "Tuesday,Thursday,Saturday"
  4 => "Tuesday"
  5 => "Monday,Wednesday"
  6 => "Saturday,Sunday"
  8 => "Wednesday"
  9 => "Saturday"
  10 => "Tuesday"
  11 => "Monday,Sunday"

in this ordery (by days of the week)

  2 => "Monday"
  5 => "Monday,Wednesday"
  11 => "Monday,Sunday"
  1 => "Tuesday"
  4 => "Tuesday"
  10 => "Tuesday"
  3 => "Tuesday,Thursday,Saturday"
  7 => "Tuesday,Friday"
  8 => "Wednesday"
  0 => "Thursday,Sunday"
  9 => "Saturday"
  6 => "Saturday,Sunday"

In the end I'll need to define the starting day but hopefully it should be easy to generalize the solution.

Thanks!

UPDATE

Next question is how do I rearrange the

    $day_map = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'];

to start from today date('l'). So if today's Fridey I would get

    $rearranged_day_map = ['Friday', 'Saturday', 'Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday'];

And the answer to the updated question (the answer to the original question is below):

    //days
    $day_map = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'];
    //order days to start from tomorrow
    $today = date('N'); // get today's day of the week
    $day_map_rearranged = array_merge(array_slice($day_map, $today),array_slice($day_map, 0, $today));

Answer 1

As others have advised, you'll need to use uasort for this one. What I would do is explode the string first. Then create a default mapping for a day sequence (Mon - Fri) and use that for the sorting.

Here's the dirty idea:

// default order
$day_map = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'];
uasort($input_array, function($a, $b) use ($day_map) {
    $c = explode(',', $a); $d = explode(',', $b);
    for($i = 0, $len = count($c); $i < $len; $i++) {
        $d1 = @array_search($c[$i], $day_map);
        $d2 = @array_search($d[$i], $day_map);
        if($d1 == $d2) {
            continue; // skip, check the next column
        }
        return $d1 - $d2;
    }
});

Sample Out