2014-06-30 14:41 阅读 76

创建一个简单的AJAX / jQuery / PHP SELECT * / JSON

Basically I want to know how I can pass an array from PHP to JSON and be able to use it in my js file, where the jQuery is, and with jQuery I'm using the $.ajax({}).

I have so far:

$db = new PDO('mysql:host=localhost;dbname=names', 'username', 'password');
$stmt = $db->query('SELECT * FROM names ORDER BY name DESC');
$results = $stmt->fetchAll();

$namesArray = array();
foreach ($results as $row) {
    array_push($namesArray, '<li>' . $row['name'] . '</li>');

echo json_encode($namesArray);

As for the jQuery / AJAX, I'm not really sure how I should go about it. The only thing I want to do in PHP is make it select all the data from the database, (which has one col, names), and store them in an array via the foreach, and I pushed them to a separate array.

How would I go about the jQuery / AJAX? I've searched everywhere and the only thing I can find is how to make search functions with AJAX, although I don't want to search for one name, I want every name in the database to show up. Thanks in advance.


in my index.html file I have linked the .js file, and also in there I have a unordered list with the class: "names".

So, for my jQuery file, or .js file, I have

$(document).ready(function() {
        type: "POST",
        dataType: "json",
        url: "post.php",
        data: { },
        cache: false,
        success: function() {


but I'm not sure on what goes in the data variable, and also the success function I'm confused on too.

If I have forgotten any vital information on figuring this out please let me know :)

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1条回答 默认 最新

  • 已采纳
    dsfphczao23473056 dsfphczao23473056 2014-06-30 14:46

    May be something like this with jQuery AJAX:

        type : 'POST',
        url : 'path/to/your/file.php',
        success : function(data){
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