如何传递到href中的不同信息

Question

i am trying to output some information based on the edit in the code below :

echo "<td>".$rows['td']."<a href='edittd.php?edit=$rows[Nom_Matiere]'> edit <a></td>";

but the problem is that i want to output this information using 2 different information $rows[Nom_Matiere] and $rows[Number] how can i do that i tried those options :

1*

echo "<td>".$rows['td']."<a href='edittd.php?edit=$rows[Nom_Matiere] and $rows[Number]'> edit <a></td>";

2*

  echo "<td>".$rows['td']."<a href='edittd.php?edit=$rows[Nom_Matiere] && $rows[Number]'> edit <a></td>";

but they didn't work ,please is there suggestions how i can do that ,and the edittd.php:

echo mysql_error();
if(!empty($_SESSION['LoggedIn']) && !empty($_SESSION['Mail_Enseignant']))
{echo mysql_error();
$username = $_SESSION['Mail_Enseignant'];      
    echo mysql_error();
//query the database
if(isset($_GET['edit'])){
        $Nom_Matiere = $_GET['edit'];
            $Number = $_GET['edit'];
        $res = mysql_query("select Nom_Etudiant,Numero from etudiant,groupe,matiere where matiere.`Nom_Matiere`= '".$Nom_Matiere."' and groupe.`Number`= '".$Number."' and matiere.`Id_Specialite`=groupe.`Id_Specialite`")or die($myQuery."<br/> <br/>".mysql_error());
while($rows = mysql_fetch_array($res)):

    echo "<tr class='light'>";
    echo "<td>".$rows['Nom_Etudiant']."</td>";  
    echo "<td>".$rows['Numero']."</td>";        
endwhile;}
            ?>

Answer 1

You need a parameter for the second value there.

 echo "<td>{$rows['td']}<a href='edittd.php?edit={$rows['Nom_Matiere']}&number={$rows['Number']}'> edit <a></td>";