donglianjiang9321 2014-03-23 19:25 采纳率: 0%
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PHP代理 - 使用cURL上传文件

I'm currently building an application written in AngularJS with a Laravel based API for the backend, data is passed via a simple PHP proxy to keep my API key secure(ish).

For POST requests the proxy simply json_decode PHPs input stream (php://input) as Angular serialises POST data to JSON, passes it through http_build_query then forwards it via cURL to the API - so far, it's been working flawlessly.

I've managed to get the file over to the proxy - however, as it's sent with multipart/form-data headers, it's only available in $_FILES and not the input stream.

Relevant snippets from the proxy below:

function curlRequest($url, $post = false, $data = null)
{
  $ch = curl_init();

  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

  if($post == true) {
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data));
  }

  $data = curl_exec($ch);
  $httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);

  curl_close($ch);
}

$data = json_decode(file_get_contents('php://input'), true);
$data['api_key'] = API_KEY;

// File data available here!
var_dump($_FILES);

$result = curlRequest(URL, true, $data);

The problem I'm having, I'm unsure how to correctly POST the file to the API endpoint once I've got it in $_FILES.

Any help would be greatly appreciated!

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1条回答 默认 最新

  • dshgnt2008 2014-03-23 19:32
    关注

    This may send files over as well :

    $data = json_decode(array_merge($_REQUEST, $_FILES));
    $data['api_key'] = API_KEY;
    
    // File data available here!
    var_dump($_FILES);
    
    $result = curlRequest(URL, true, $data);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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