多个下拉列表中的多个值

Question

Hello i'm working on some project and i have 6 dropdowns and every has it values

Example in first dropdown i have:

<input type="checkbox" id="dt1" name="dt1" value="1">20 kW<br> 
<input type="checkbox" id="dt2" name="dt2" value="2">40 kW <br> 
<input type="checkbox" id="dt3" name="dt3" value="3">60 kW <br> 

And in Other i have:

<input type="checkbox" id="stv1" name="stv1" value="6">500 L<br> 
<input type="checkbox" id="stv2" name="stv2" value="7">1000 L<br> 
<input type="checkbox" id="stv3" name="stv3" value="8">"2000 L<br> 

But now i have many questions first how can i make drop down with only one selection? second question is how can i give result when someone choose from drop down one value 1 and from drop down 2 value 8 how can i make value1+value8=link?

Till now i have used

if (containsOnly(values, ['1', '8'])) {
        alert('something');
    }

but now i dont need alert, i need link so if someone can help me or do something on JS Fiddle that would be great

my latest work on this topic was this http://jsfiddle.net/KyleMuir/bUdra/5/ but now its not just choice a b or c, it must be choice a drop down with 3 or 4 choices and without alert.. If someone could help me it would be great

Answer 1

with this code you can get both values in the same file or in an other file just edit it to what you need:

<?php
    if($_POST) {
    $dd1 = $_POST['dropdown1'];
    $dd2 = $_POST['dropdown2'];

header('Location: file.php?dd1='.$dd1.'&dd2='.$dd2);
exit();
}
?>

<form action="" method="post">
    <select name="dropdown1">
        <option value="20">20 kW</option> 
        <option value="40">40 kW</option> 
        <option value="60">60 kW</option>
    </select>

    <select name="dropdown2">
        <option value="500">500 L</option> 
        <option value="1000">1000 L</option> 
        <option value="2000">2000 L</option>
    </select>
    <input type="submit" value="Calculate">
</form>

file.php could then be something like:

<?php
$dd1 = strip_tags($_GET['dd1']);
$dd2 = strip_tags($_GET['dd2']);

echo $dd1; //should give you the value from dropdown1
echo $dd2; //should give yout the value from dropdown2
?>

<!-- the php variables can also be used in javascript -->
<!-- don't know for sure if this is the correct way to use php in javascript but atleast should be something like this -->
<script type="text/javascript">
var dropdown1 = <?php $dd1; ?>;
var dropdown2 = <?php $dd2; ?>;
</script>