PHP正则表达式 - 在这种情况下我现在做错了什么？

Question

using the regular expression:

$pattern = "/adminvalues = \"\([^']+, '[^']+', MD5\('[^']+'\), '[^']+','[^']+','[^']+',[^']+,[^']+\)\";/";
preg_match($pattern, $data, $results);
print_r($results);

searching the following text (values within brackets can change... hence the need for regex...):

adminvalues = "(NULL, 'Admin12345', 'MD5(Admin12345)', 'Admin12345', 'Admin12345', 5, 0, 0)";

so am looking for a pattern (in reg-ex) that matches essentially the following (I think...):

[adminvalues = "(] [any character] [, '] [any character] [', MD5('] [any character] ['), '] [any character] [', '] [any character]  [', ] [any character] [, ] [any character] [, ] [any character] [)";]

Where: Any character is one or more of any combination of (letter / number / symbol)

I get no matches using the PHP code at the top - so I've obviously done something wrong! I just can't spot the error myself. (I only started using regex this morning really...) What have I done wrong? :)

Solve: (Thanks to Amal Murali) Using htmlspecialchars() when reading the php script being used as $data (rather than just to display contents)

Answer 1

Try the following regex:

$pattern = <<<PATTERN
~
  adminvalues\s*=\s*
  "
  \(                  
    [^,]+,\s*
    '[^']+',\s*
    MD5\('[^']+'\),\s*
    '[^']+',\s*
    '[^']+',\s*
    \d,\s*
    \d,\s*
    \d\s*
  \)
  ";
~xm
PATTERN;

Regex101 Demo