用于将字符串拆分为数组的正则表达式

Question

I got a string like this:

== Paragraph == 
=== title 1 ===
content

=== Title 2 ===
other content 

== Paragraph 2 ==
=== asd1 ===
dfdsfdsfdsfdsfdsfsdfdsf

=== asd2 ===
fgdfgfdgfdgfdgfdgfdgfdg

I'm trying to parse it into array like this:

$arr = array( 
    array("title"=>"Paragraph", "content" => "=== title 1 ===
content

=== Title 2 ===
other content "),
array("title"=>"Paragraph 2", "content" => "=== asd1 ===
dfdsfdsfdsfdsfdsfsdfdsf

=== asd2 ===
fgdfgfdgfdgfdgfdgfdgfdg"));

I've tried this expession for getting paragraph names:

preg_match_all("@== (.*?) ==.*?@is", $data, $paragraphs);

but this expresion isn't working as I want, because it doesn't match the whole paragraph the output is like this and it doesn't get the contents:

Array
    (
        [0] => Paragraph
        [1] => title 1
        [2] => Title 2
        [3] => Paragraph 2
        [4] => asd1
        [5] => asd2
    )

I have also tried ( nl2br cuz I don't know how to use new line in regex )

$data = nl2br($data);
preg_match_all("@== (.*?) ==<br />.*?@is", $data, $paragraphs);

but the result is something like this:

[0] => Array
    (
        [0] => == Paragraph == <br />
=== title 1 ===<br />
content<br />
<br />
 === Title 2 ===<br />
 other content <br />
 <br />
 == Paragraph 2 ==<br />
    )

I'm not understanding the regular expresions good and I can't figure out how to solve my problem.

Answer 1

You could maybe try this regex?

@(==[^=]+==)(.+?(?=[^=]==[^=]|$))@s

Demo on regex101.