如果条件不按预期方式工作

Question

the current page is getting the variables item and code from query string,so according to my code it should go into any of the first three conditions... but its going into the last else conditon.. while echoing the values $a and $i, i am getting 2 and A-1-1 respectively.

$a=$_GET['code'];
$i=$_GET['item'];
if($a==1 && $i!='')
{
  header("location:http//:www.abc.com");
}
else if($a==2 && $i!='')
{
  header("location:http://www.xyz.com");
}
else if($a==3  && $i!='')
{
 header("location:http://www.xpqr.com");
}
else if($a==1)
{
  header("location: http://www.a1bc.com");
}
else if($a==2)
{
  header("location:http://www.x1yz.com");
}
else if($a==3)
{
  header("location:http://www.x1pqr.com");
}
else
{
   echo "ERROR";
}

can someone help me find the issue why the if else not working in the expected manner.

Answer 1

you need to use the equality operator: == double equal

if($a==1 && $i!='')

single equal is the assignment operator.