File_get_contents获取远程页面的源代码，然后只显示特定的div

Question

exactly as its descriped in the title currently my code is:

<?php
    $url = "http://www.vipboxsports.me/football/23863/1/chelsea-tv-live-stream-online.html";
    $html = str_get_html($url);
    $elem = $html->find('div[id=streambox]', 0);
    echo $elem;
?>

but at this point its not working what is the problem with code above

Answer 1

<?php
    $url = "remotesite.com/pages/page1.html";
    $html = str_get_html($url);
    $elem = $html->find('div[id=mydiv]', 0);
    echo $elem;
?>