duanchun2349 2013-06-17 15:47
浏览 67
已采纳

PHP SQL数组没有返回任何内容

Can I have some advice on where I'm going wrong with this Query?

 $entry_id = '1';
 $accident_road = $form_data[58]["id"]; //print_r returns "116"

        $accident_road_array = $wpdb->get_results(
          "SELECT id FROM wp_rg_lead_detail
           WHERE field_number = '$accident_road'
           AND 'lead_id' = '$entry_id' ",
           ARRAY_A); 


 print_r returns 'Array()'
  • 写回答

2条回答 默认 最新

  • duankang5285 2013-06-17 15:55
    关注

    I assume lead_id is a field in DB so you don't need quotes for it:

    AND lead_id = '$entry_id'
    

    You're also going wrong by putting variables directly into the query, you make your app vulnerable to SQL injections. consider using prepared statements.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥100 set_link_state
  • ¥15 虚幻5 UE美术毛发渲染
  • ¥15 CVRP 图论 物流运输优化
  • ¥15 Tableau online 嵌入ppt失败
  • ¥100 支付宝网页转账系统不识别账号
  • ¥15 基于单片机的靶位控制系统
  • ¥15 真我手机蓝牙传输进度消息被关闭了,怎么打开?(关键词-消息通知)
  • ¥15 装 pytorch 的时候出了好多问题,遇到这种情况怎么处理?
  • ¥20 IOS游览器某宝手机网页版自动立即购买JavaScript脚本
  • ¥15 手机接入宽带网线,如何释放宽带全部速度