I looked a lot on the internet and wasn't able to find the answer i need, so here i come to you. What i have : A database which look like this :
name latitude longitude
---- --------- ----------
foo 13.323 -51.356
foo 54.698 2.487
What i want to do : I need to retrieve the latitude and longitude from a mysqli request done with php and use it in a function that i defined.
My problem : I'm trying to use xmlrequest but it apparently doesn't work.
The code : JS :
var selI = document.getElementById("nameIti");
selI.onchange = function(){
var val = this[this.selectedIndex].getAttribute("value");
showMark(val);
}
function showMark(str){
var xhr;
if(str==""){
return;
}
if(window.XMLHttpRequest){
xhr=new XMLHttpRequest();
}
else{
xhr=new ActiveXObject("Microsoft.XMLHTTP");
}
xhr.onreadystatechange=function(){
if(xhr.readyState==4 && xhr.status ==200){
var object = JSON.parse(xhr.responseText);
for(var a in object){
newMark(v['lat'], v['lng']);
document.getElementById("pi").innerHTML=JSON.parse(xrh.responseText); // This is a test to display any kind of result.
}
}
}
xhr.open("GET", "getpos.php?q="+str, true);
xhr.send();
}
PHP :
<?php
$nom = $_GET['q'];
include("connexion.php");
$con = connect_LIF4();
$req1= "SELECT Latitude, Longitude FROM etape LEFT JOIN itineraires ON NomLieu=nomEtape WHERE nomIti LIKE '%$nom%'";
$result1 = mysqli_query($con, $req1);
$data = array();
while($row = mysqli_fetch_array($result1){
$data['lat'] = $row['Latitude'];
$data['lng'] = $row['Longitude'];
$resp[] = $data;
}
echo json_encode($resp);
mysqli_close($con);
?>
I tried to use newMark(lat, lng)(Which i coded and works fine) with random values, in showMark outside the onreadystatechange and it works, but i need to use it with the values retrieved from the php.