douying4203 2014-12-03 16:24
浏览 334
已采纳

循环遍历php数组并在指定位置插入key => value

I have this array:

[
    {"key": 1, "title": "Animalia", "expanded": true, "folder": true, "children": [
        {"key": 2, "title": "Chordate", "folder": true, "children": [
            {"key": 3, "title": "Mammal", "children": [
                {"key": 4, "title": "Primate", "children": [
                    {"key": 5, "title": "Primate", "children": [
                    ]},
                    {"key": 6, "title": "Carnivora", "children": [
                    ]}
                ]},
                {"key": 7, "title": "Carnivora", "children": [
                    {"key": 8, "title": "Felidae"}
                ]}
            ]}
        ]}
    ]}
]

I want to loop trough the array and when the "key" equals a specified number (let's say 5) I want to insert a "selected": true key=>value

Is there such a possibility?

  • 写回答

1条回答 默认 最新

  • duanhan9334 2014-12-03 20:45
    关注

    Well just make your JSON string to a valid PHP array with $myArray = json_decode(JSONString)

    Then you could access the point you want like array_push($myArray[0]["1"], "myValue")

    I will need the exact position where you want to add which type of value to give you a better hint... :-)

    Edited with working code

    You have to do a recursive search over your JSON structure, to find your value and to set the Value you need... I wrote you a short php function that does that trick...

    As you see, the function takes to params and gives you back the ready php array for further use of it... Just call it like descriped below....

    Usage Example

    $myArray = json_decode($myJSON, true);
    $myArray = setSelectedForKey($myArray, "6");
    echo(json_encode($myArray));
    

    Following the function you need:

    function setSelectedForKey($searchArray, $searchKey) {
            for ($i = 0; $i < count($searchArray); $i++) {
                if ($searchArray[$i]["key"] == $searchKey) {
                    $searchArray[$i]["selected"] = true;
                } else {
                    if (is_array($searchArray[$i]["children"])) {
                        $searchArray[$i]["children"] = setSelectedForKey($searchArray[$i]["children"], $searchKey);
                    }
                }
            }
            return $searchArray;
        }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 MCNP里如何定义多个源?
  • ¥20 双层网络上信息-疾病传播
  • ¥50 paddlepaddle pinn
  • ¥20 idea运行测试代码报错问题
  • ¥15 网络监控:网络故障告警通知
  • ¥15 django项目运行报编码错误
  • ¥15 请问这个是什么意思?
  • ¥15 STM32驱动继电器
  • ¥15 Windows server update services
  • ¥15 关于#c语言#的问题:我现在在做一个墨水屏设计,2.9英寸的小屏怎么换4.2英寸大屏