在PHP / MySQL中创建没有HTML代码的换行符

Question

I have this PHP Code:

$address='';
if($_POST["address1"] > '') {
    $address.=$_POST["address1"];
}
if($_POST["address2"] > '') {
    $address.=$_POST["address2"];
}
if($_POST["address3"] > '') {
    $address.=$_POST["address3"];
}
if($_POST["town"] > '') {
    $address.=$_POST["town"];
}
if($_POST["county"] > '') {
    $address.=$_POST["county"];
}
if($_POST["postcode"] > '') {
    $address.=$_POST["postcode"];
}

It then inserts a row into a database using the $address variable

How can i ensure there is a non-html line break for each address line?

Answer 1

Put the address fields in an array, then use implode() to combine them with newlines:

$addr_array = array();
foreach (array('address1', 'address2', 'address3', 'town', 'county', 'postcode') as $field) {
    if ($_POST[$field] > '') {
        $addr_array[] = $_POST[$field];
    }
}
$address = implode("
", $addr_array);