doujiao6116 2014-05-23 03:00
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php mysqli多查询重新排序自动增量id [关闭]

Hi so I am using a mysqli multi query for the first time. I have tried this query in phpmyadmin and it works but when running this query I get the error below.

if(isset($_GET['del'])){

    $delete_id = $_GET['del'];

    $delete_query = "DELETE FROM `gallerycontent` WHERE `pic_id` = '$delete_id';";
    $delete_query. = "SET @num = 0;";
    $delete_query. = "UPDATE `gallerycontent` SET `pic_id` = @num := (@num+1);";
    $delete_query. = "ALTER TABLE `gallerycontent` AUTO_INCREMENT =1;";

    if(mysqli_multi_query($link, $delete_query)){
        echo "<script>alert('The image has been deleted')</script>";
        echo "<script>window.open('reviewgallery.php','_self')</script>";
    }
}

Here is the error I get

Parse error: syntax error, unexpected '=' in C:\wamp\www\mysqli\deleteimage.php on line 13

which is the line

$delete_query. = "SET @num = 0;";

Also does it for the other vars.

Not sure what the answer and I have not been able to find much help on this one. Thanks for your help in advance.

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1条回答 默认 最新

  • douyinmian8151 2014-05-23 03:01
    关注

    Your concatenation operator is incorrect : it should be .= instead of . = :

    $delete_query = "DELETE FROM `gallerycontent` WHERE `pic_id` = '$delete_id';";
    $delete_query .= "SET @num = 0;";
    $delete_query .= "UPDATE `gallerycontent` SET `pic_id` = @num := (@num+1);";
    $delete_query .= "ALTER TABLE `gallerycontent` AUTO_INCREMENT =1;";
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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