设置var的缩写，以2个变量中较大者为准

Question

I have 2 different possible values I use in an equation. I want to select whichever one exists and is greater using the least amount of code. It's possible neither variable exists, in which case year = 0, but one or both might exist. I.e:

if(isset($this->average['year'] || isset($this->Listings['year']) {
$year = whichever is greater of the above.
} else {
$year = 0;
}

It seems like there must be a shorter/ less messy way to do this than:

if (isset($this->average['year']) && ($this->average['year'] > $this->Listings['year']) {
   $year = $this->average['year'];
} elseif( isset($this->Listings['year'])) {
   $year = $this->Listings['year'];
} else {
  $year = 0;
}

Thanks

Answer 1

Using max and the ternary operator to do isset checks on both variables you can shorten it to this:

$year = max(array(
    isset($this->average['year']) ? $this->average['year'] : 0,
    isset($this->Listings['year']) ? $this->Listings['year'] : 0
));