duangenshi9836 2014-04-01 17:42
浏览 36

$ .getJSON(... php,function)else

I'm working with JSON to make my login script, and so I'm using the following in my script:

$.getJSON("link to PHP where to get the JSON data from", function (data) { // THE CODE TO BE EXECUTED });

So when there is an data return from the PHP in JSON, the code will be executed, but what is the best way to make an else structure? So when there is no return from PHP/JSON, to execute an other code?

Thanks in advance

  • 写回答

2条回答 默认 最新

  • doulu8446 2014-04-01 17:44
    关注

    Use jQuery's promises. From the docs:

    var jqxhr = $.getJSON( "example.json", function() {
      console.log( "success" );
    })
      .done(function() {
        console.log( "second success" );
      })
      .fail(function() {
        console.log( "error" );
      })
      .always(function() {
        console.log( "complete" );
      });
    
    评论

报告相同问题?

悬赏问题

  • ¥15 划分vlan后不通了
  • ¥15 GDI处理通道视频时总是带有白色锯齿
  • ¥20 用雷电模拟器安装百达屋apk一直闪退
  • ¥15 算能科技20240506咨询(拒绝大模型回答)
  • ¥15 自适应 AR 模型 参数估计Matlab程序
  • ¥100 角动量包络面如何用MATLAB绘制
  • ¥15 merge函数占用内存过大
  • ¥15 Revit2020下载问题
  • ¥15 使用EMD去噪处理RML2016数据集时候的原理
  • ¥15 神经网络预测均方误差很小 但是图像上看着差别太大