douzi8548 2014-04-01 17:31
浏览 6
已采纳

在PHP中将对象添加到字符串

I am a bit confused about how to add an object to a string.

I am trying to add the $this->getUserId(); (which contains the userId of the user).

$fileName = "user_.$this->getUserId()".".$fileExt";
  • 写回答

3条回答 默认 最新

  • dongye9182 2014-04-01 17:37
    关注

    This should work:

    $fileName = "user_{$this->getUserId()}.$fileExt";
    

    It should give you:

    user_1.ext
    

    See the PHP manual on strings, more specifically the part about curly braces and 'complex' parsing.

    For normal variables you can place them in double quoted strings and they will be parsed. For more complex things like expressions you need to wrap them in {} so that they will be parsed.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥20 基于MSP430f5529的MPU6050驱动,求出欧拉角
  • ¥20 Java-Oj-桌布的计算
  • ¥15 powerbuilder中的datawindow数据整合到新的DataWindow
  • ¥20 有人知道这种图怎么画吗?
  • ¥15 pyqt6如何引用qrc文件加载里面的的资源
  • ¥15 安卓JNI项目使用lua上的问题
  • ¥20 RL+GNN解决人员排班问题时梯度消失
  • ¥60 要数控稳压电源测试数据
  • ¥15 能帮我写下这个编程吗
  • ¥15 ikuai客户端l2tp协议链接报终止15信号和无法将p.p.p6转换为我的l2tp线路