doupu1949 2014-03-26 11:48
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从AJAX调用REST服务方法

I am calling a REST service method from AJAX.

$(document).ready(function () {
        var xmml = getXmlLoginRequest();
        var wsdlURL = getWSDL('search');
        $.ajax({
            type: "POST",
            url: wsdlURL,   
            data: xmml, 
            contentType: "text/xml;charset=utf-8",
            dataType: 'text',
            success: function (result) {
                debugger;
                alert(" success" + result);
            },
            error: function (jqXHR, textStatus, errorThrown) {
                debugger;
                alert(" error" + "jq :" + jqXHR + "textStatus :" + textStatus + "error : " + errorThrown);
            }
        });

        function getXmlLoginRequest() {
            debugger;
            var xml = '<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> \
             <soap:Body> \
                <search> \
                <qry>svein </qry> \
                </search> \
             </soap:Body> \
           </soap:Envelope>';

            return xml;
        }
        function getWSDL(methodName) {
            debugger;
            var url = 'http:/MyURL/search.php?username=abc&password=def';
            return url;
        }

    });  

I am getting result as empty in success block. If I change dataType to text, I get an exception in Failure block which says cannot parse NULL.
Am I writing incorrect syntax? When I run the url on browser with method and its parameters, it gives proper result.

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  • douguxun6866 2014-03-26 11:58
    关注

    What I see here is SOAP and not REST. You should try jQuery SOAP Plugin and not jQuery AJAX method directly.

    Moreover WSDL Url is not the service URL, but URL of service description. The service URL is located in WSDL.

    Service should be located on the same domain as your html page, because of same-origin-policy.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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