dongsuiwo0279 2014-03-23 22:40
浏览 13
已采纳

如何获取包含点的网址[关闭]

I'm trying to get the url from sample below link using php get but I'm missing something.

Example link:

example.com/go/?url=http://example2.com

and using the below code:

<?php
$url = $_GET["url"];
echo $url;
?>

and all i can see is 403 error, I see now that error is from dot (.) in url, but how can I correct it?

  • 写回答

1条回答 默认 最新

  • duanfang7270 2014-03-23 22:42
    关注

    You should urlencode the parameter to ensure its not being interpreted wrong, when sending the request to the server and use urldecode on the server to revert it back.

    Also the 403 error code is the web serving telling you permission denied for some reason you have to investigate. Maybe look at the logs for your webserver.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 关于#MATLAB#的问题,如何解决?(相关搜索:信噪比,系统容量)
  • ¥500 52810做蓝牙接受端
  • ¥15 基于PLC的三轴机械手程序
  • ¥15 多址通信方式的抗噪声性能和系统容量对比
  • ¥15 winform的chart曲线生成时有凸起
  • ¥15 msix packaging tool打包问题
  • ¥15 finalshell节点的搭建代码和那个端口代码教程
  • ¥15 Centos / PETSc / PETGEM
  • ¥15 centos7.9 IPv6端口telnet和端口监控问题
  • ¥20 完全没有学习过GAN,看了CSDN的一篇文章,里面有代码但是完全不知道如何操作