doumeng1897 2013-06-30 06:13
浏览 7
已采纳

在值比较后选择返回选择控件

I am trying to remove as much code from within my html as possible without using a template framework and I am unsure why 'selected' is not being returned to define 'selected' for the options of a select box. $row_status populates the options ok and $status has a value assigned.

Am I way off on this?

    <select id='status'>
     <option>Please Select</option>
     <?php while($row_status = mysqli_fetch_assoc($results_status)): ?>
     <option <?php sel($row_status['list_value'],$status)?> >  <?php echo $row_status['list_value'] ?>  </option>
     <?php endwhile; ?>
    </select>

    function sel($rs, $status){
       if ($rs==$status){
          return "selected";
       }
    }
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2条回答 默认 最新

  • drctyr2869 2013-06-30 06:16
    关注

    You are only returning a value, not echoing it.

    <?php echo sel(...); ?>
    

    should work for you. You also might want to change your function to return an empty string in case the condition is not true.

    function sel($rs, $status) {
        return ($rs == $status) ? "selected" : "";
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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