具有多个可选结尾的正则表达式

Question

I have the following URIs:

• /controller/method/arg1/arg2
• /controller/method/arg1/arg2/ <- tailing slash
• /controller/method/arg1/arg2?param=1&param=2 <- tailing query string

I need a regular expression to extract always /controller/method/arg1/arg2, while keeping in mind that it can end with /, ? or ? + some characters.

This:

^\/.*\??

is not working for me, as it is taking the chars before ?.

I don't care if the resulting string includes / or ? at the end, I can trim it.

Answer 1

I'm sure one can think of more fancy regex's, but as far as I can see, the simplest possible matching regex would be;

^[^?]*

It cuts everything after ? off, and the other matches are - as you say - easily handled by trimming.

A ReFiddle to test with.