duan00529 2013-05-07 15:54 采纳率: 100%
浏览 17
已采纳

php消除for循环中的空白选项行[关闭]

I have a strange thing happening and I don't know why. I have a multidimensional array that looks like this:

Array ( [0] => Array ( 
              [title] => I'm a title
              [desc] => Value1*Value2*Option1*Option2*Option3*Value3))

When I output it into a table everything works perfectly except the option values. I get a blank option after each value. Why is that? Here's what I have:

for ($j=0; $j<count($_SESSION[$ses]); $j++){
    echo '<tr><td>'.$_SESSION[$ses][$j]['title'].'</td>';
    $desc = explode("*", $_SESSION[$ses][$j]['desc']);
    echo '<td>$'.$desc[0].'</td><td>'.$desc[1].'</td><td><select>';
for ($i=2; $i<count($desc)-1; $i++){
    echo '<option>'.$desc[$i].'<option>';
}
    echo '</select></td>
}

I couldn't find a solution anywhere. Any advice? It's not the end of the world but it just doesn't look ideal. Thanks in advance.

  • 写回答

1条回答 默认 最新

  • duanchuiwen6694 2013-05-07 15:58
    关注

    You forgot to close the option tag

    This should do it.

    for ($j=0; $j<count($_SESSION[$ses]); $j++){
        echo '<tr><td>'.$_SESSION[$ses][$j]['title'].'</td>';
        $desc = explode("*", $_SESSION[$ses][$j]['desc']);
        echo '<td>$'.$desc[0].'</td><td>'.$desc[1].'</td><td><select>';
    for ($i=2; $i<count($desc)-1; $i++){
        echo '<option>'.$desc[$i].'</option>'; /* This one you forgot */
    }
        echo '</select></td>
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 R语言Rstudio突然无法启动
  • ¥15 关于#matlab#的问题:提取2个图像的变量作为另外一个图像像元的移动量,计算新的位置创建新的图像并提取第二个图像的变量到新的图像
  • ¥15 改算法,照着压缩包里边,参考其他代码封装的格式 写到main函数里
  • ¥15 用windows做服务的同志有吗
  • ¥60 求一个简单的网页(标签-安全|关键词-上传)
  • ¥35 lstm时间序列共享单车预测,loss值优化,参数优化算法
  • ¥15 Python中的request,如何使用ssr节点,通过代理requests网页。本人在泰国,需要用大陆ip才能玩网页游戏,合法合规。
  • ¥100 为什么这个恒流源电路不能恒流?
  • ¥15 有偿求跨组件数据流路径图
  • ¥15 写一个方法checkPerson,入参实体类Person,出参布尔值