PHP strtotime返回整年而不是一天

Question

I am currently using PHP ROUND , ABS , STRTOTIME to calculate the difference between two dates.

The calculation works until you select a $_SESSION['b_checkout'] from a new year. i.e. if the b_checkin is Dec 30 and the b_checkout is Dec 31, this returns the correct $no_nights as 1 day.

$_SESSION['b_checkin'] and $_SESSION['b_checkout'] are using 'D F jS Y' date format. e.g.

$_SESSION['b_checkin'] = "Wednesday, 31 December, 2014"
$_SESSION['b_checkout'] = "Thursday, 1 January, 2015"

$no_nights = round(abs(strtotime($_SESSION['b_checkout']) - strtotime($_SESSION['b_checkin']))/(60*60*24));

Currently this outputs (echo $no_nights) 363 days instead of 1 day. What is the problem?

Answer 1

Remove all the commas and see it works!

$b_checkin = "Wednesday 31 December 2014";
$b_checkout = "Thursday 1 January 2015";

$no_nights = round(abs(strtotime($b_checkout) - strtotime($b_checkin))/(60*60*24));
echo $no_nights;

When php can't interpret the year correctly, it uses the current year for parsing. thats how you are getting 363 days as result.