dskm94301
2018-10-15 14:18
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PHP strtotime获取给定年份的最后一天

How can i get the last day of a year passed as parameter using strtotime?

I try this but the results are not the correct last days :

$yearEnd2015 = date('Y-m-d', strtotime('last day of december this year -3'));
    $yearEnd2016 = date('Y-m-d', strtotime('last day of december this year -2'));
    $yearEnd2017 = date('Y-m-d', strtotime('last day of december this year -1'));
    $yearEnd     = date('Y-m-d', strtotime('last day of december this year'));

    echo " <br>2015 : ".$yearEnd2015;
    echo " <br>2016 : ".$yearEnd2016;
    echo " <br>2017 : ".$yearEnd2017;
    echo " <br>2018 : ".$yearEnd;
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