将自定义日期格式转换为用户友好

Question

I currently have the following code in PHP which echo's a date from a mySQL database

//for an example
$card_info[0]['Player_DOB'] = "24/6/1987";

<td><?=$card_info[0]['Player_DOB'];?></td>

How could I parse this with 1 simple line to display a user friendly date? I know I could do something like explode($card_info[0]['Player_DOB'], "/") blah blah blah but that's the long process.

So basically is their anyway to do this with just 1 line of code to display something like this

24th of June, 1987

Answer 1

You can create your own function to parse that kind of dates or do:

echo DateTime::createFromFormat("d/m/Y","24/6/1987")->format('r');