从View中完全删除<li>标记

Question

I have an array object from a son API and I want to display only the first 3 items and hide the rest of the items.

Unfortunately when I try to hide the rest of the items from the view it still shows that a list was there but hidden. I want to hide that completely without destroying the values in that list.

My code below

$characters = json_decode($data);
foreach ($characters as $character) {

    <?php echo "<li style='display:none'>".$character->name . '<br>'."</li>"; ?>

}

Answer 1

You can use array_slice method to create another array with reduced number of items (for your example, that'd be 3).

Solution for your Example:

<?php echo "<li>". array_slice($character, 0, 3)->name . '<br>'."</li>"; ?>

More info about array_slice method:

array_slice() returns the sequence of elements from the array array as specified by the offset and length parameters.

array_slice(array,start,length,preserve)

array: The input array.

offset: number

• The offset parameter denotes the position in the array, not the key. If offset is non-negative, the sequence will start at that offset in the array. If offset is negative, the sequence will start that far from the end of the array.

length: number

• If length is given and is positive, then the sequence will have up to that many elements in it.

• If the array is shorter than the length, then only the available array elements will be present.

• If length is given and is negative then the sequence will stop that many elements from the end of the array.

• If it is omitted, then the sequence will have everything from offset up until the end of the array.

preserve_keys: boolean

• array_slice() will reorder and reset the integer array indices by default. This behavior can be changed by setting preserve_keys to TRUE. String keys are always preserved, regardless of this parameter.