从DateTime对象中分隔日期属性

Question

Unable to separate the date property from the DateTime object. What do I do?

I have used the following code:

while( $fetch = sqlsrv_fetch_array( $stmt , SQLSRV_FETCH_ASSOC) ) {
    //echo '<pre>'; 
    print_r($fetch); exit;
    $date=$fetch['Dt_Installment_Date'];
    echo '<pre>'; print_r($date); exit;
}

The current output that I am getting is as follows:

<pre>DateTime Object
    (
        [date] => 2019-01-18 00:00:00.000000
        [timezone_type] => 3
        [timezone] => Europe/Berlin
    )

I want to get only the [date] property and nothing else.

Answer 1

That's how you can format your DateTime object and convert into a String.

// Y : means year , m : means months , d : means days. and you can change format by seperating "/" or using same with "-"
$result = $date->format('Y-m-d');

echo $result;

Output is 2019-01-18