显示图像而不是变量的值[重复]

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• The 3 different equals 5 answers

I'm just getting to know PHP so please bear with me if my question is not clear. I have a user registration page that collects a field called "zodiac" which is uploaded to the database. I can easily call the variable $zodiac and the value, let's say, "Aries" is displayed on the desired user's page depending on who is logged in. However, instead of the text, I'd like to display a corresponding image file on the page from my local drive. I've tried the "elseif" statements but it doesn't seem to be working. Although I do get an image with the statement it doesn't seem to change when I change users:

These are properly being loaded to the desired page:

$this->table->add_row("<b>".$username."</b>&ensp;&ensp;Age:".$age."&ensp;&ensp;".$zodiac);

if($zodiac='Aries') {
   echo '<img src="../assets/images/zodiac/Aries.png" width="45" height="35" />';
    }elseif($zodiac='Taurus') {
   echo '<img src="../assets/images/zodiac/Taurus.png" width="45" height="35" />';
    }elseif($zodiac='Gemini') {
   echo '<img src="../assets/images/zodiac/Gemini.png" width="45" height="35" />';

The "elseif" statement continues to the end.

Hope this makes sense. Thanks for any input.

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Answer 1

You are mixing the assignment operator = with the equality operator ==.

// assign 1 to variable a
$a = 1

// compare variable a with 1
$a == 1

So to fix your code:

if ($zodiac == 'Aries')
{
...
}

You'll find more info about the operators and how they work here: https://secure.php.net/manual/en/language.operators.assignment.php https://secure.php.net/manual/en/language.operators.comparison.php