dpvmtdu364462 2019-06-03 14:22
浏览 49

如何使用laravel在包含的模板内部生成？

With Blade it seems the yield does not work with included parts. How can I fill a section defined inside an included part in the parent template?

It seems this is a known issue: https://github.com/laravel/framework/issues/8970

template-body.blade.php

<body>
@yield('body')
<body>

template-html.blade.php

<html>
@include('template-body')
@yield('other')
</html>

foo.blade.php

@extends('template-html')
@section('body')
Hello World! (does not work)
@endsection
@section('other')
Does work
@endsection
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1条回答 默认 最新

  • dougai6464 2019-06-03 14:42
    关注

    what you are doing will give you an error. you can include pages on the template and other sub pages. it just depends on what you are doing and how you doing it. what you should have done is:

    //app.layout
 <!DOCTYPE html>
<html>
<head>
<title>@yield('title')</title>
<your-css-files>
@yield('styles')
<your-script files>
@yield('scripts')
</head>
<body>
@include('your page')
@yield('content')

</body>
</html>

    then on your pages you do:

    @extends(app.layout)
@section('content')
<h1>This is a Heading</h1>
<p>This is a paragraph.</p>
@include('your page')
@endsection

on the samepage you can call your styles and scripts as

@section('styles')
 //css files
@stop

@section('scripts')
 // javascript files
@stop
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