Wordpress将多个插件选项作为JSON添加到一个选项中

Question

I have a plugin with multiple options, on frontend I'm using an angular app which will show all these options, so I need to save it in the DB as a JSON.

I have around 10 options, and I want all 10 to be saved in only 1 row in wp_options in a JSON format, currently update_option("fee", $_POST[$key]); saves only the last option.

if(array_key_exists('submit_settings', $_POST))
               {
                   foreach($global_settings->globals[0] as $key => $value)
                    {
                       update_option("fee", $_POST[$key]);
                    }
                   ?>
                       <div id="setting-error-settings-update" class="updated settings_error notice is-dismissible"> <stron> Settings have been saved. </strong> </div>
                   <?php

               }

               foreach($global_settings->globals[0] as $key => $value)
               {
                   echo '<label for='.$key.'>' . $key . '</label>';
                   echo '<input name='.$key.' value='.$value.' /> <br />';
               }

Answer 1

From my understanding, each time the for loop is executed you are overwriting the option fee, so everytime only the last option will be saved. What you must do is to json_enocde the whole array and save it as a single value in the DB. When you fetch it you can json_decode to get all the values.

Something like this

$fees = [ 'one' =>'opt1', 'two' => 'opt2', 'three' => 'opt3'];

update_option("fee", json_encode($options));

// In get option
$get_options = json_decode(get_option("fee"));