获取Controller Laravel内的当前路线

Question

I have several routes in web.php:

Route::get('/','PagesController@index');

Route::get('/contact','PagesController@contact');

and so on...

I need to get in my PagesController the current 'module' (index, contact or smth else).

The Controller's code:

   class PagesController extends Controller
   {
    public function index()
    {
       $menu = new Menu();

       $links = $menu->getMenu();

       //$header=url()->current(); // returns the full url, e.g. http://test.com/
       //$header=Route::current(); // error: Class Route not found

       return view("index",['links'=>$links,'header'=>$header]);
    }
}

For example, $header should be equal to "/" inside PagesController@index and $header = "contact" inside PagesController@contact.

I need the universal solution for all the modules I'll have in future.

Thanks a lot!

Answer 1

I have not had a chance to test this, however you should be able to achieve this with the following:

Route::get('/{page?}', function($page = 'index') {
    return app('App\Http\Controllers\PageController')->{$page}($page);
});

Basically, this is setting a route to have an optional $page variable. If no page name is passed (e.g. contact), we default to index.

We finally use the app() helper to call the PageController and then use the ->{$page}() syntax to call a dynamic controller method (In the default case index).

Hope this helps.