如何使用相同的名称从POST变量中获取多个值

Question

When user inputs text in 'ctext' field and press accept, I want to fill the value=" " field with user input, i achieved this but it fills all the value fields of same name in the page, how can i achieve it for different value of different ctext input? Anyone please give me solution with example, Many thanks

<?php

$connect = mysqli_connect('localhost', 'root', 'root123', 'font');
$query = 'SELECT * FROM pens ORDER by id ASC';
$result = mysqli_query($connect, $query);

if($result):
    if(mysqli_num_rows($result)>0):
        $i=0;
        while( $pen = mysqli_fetch_assoc($result) ):
        ?>
        <form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>?action=add&id=<?php echo $pen['id']; ?>">

            <div class="name pen-<?php echo $pen['id']; ?>">
                <input type="text" name="ctext[]" class="form-control" placeholder="Type your text here" value="<?php $ctext = false; if(isset($_POST['ctext'])){ $ctext = $_POST['ctext']; } echo $ctext[$i]; ?>"></input>
                <input type="hidden" name="id" value="<?php $pen['id']?>"></input>
            </div>

            <div class="btn-custom">
                <input type="submit" name="add_to_cart" class="btn btn-block" value="Accept"></input>
            </div>      
        </form>
        <?php
        $i++;
        endwhile;
    endif;
endif;

?>

Answer 1

I hope I understand what you want. You want to access the ctext for each individual $pen when printing the corresponding form.

You just need to name your <input> with a unique name and then access that value when printing. A possible solution is this:

<input type="text" name="ctext[<?php echo $pen['id']; ?>]" class="form-control" placeholder="Type your text here" value="<?php $ctext = ''; if(isset($_POST['ctext'][$pen['id']])){ $ctext = $_POST['ctext'][$pen['id']]; } echo $ctext; ?>"></input>

What does it do?

• name="ctext[<?php echo $pen['id']; ?>]" ensures a unique name for each $pen. For a $pen with id 1 this will result in name="ctext[1]".
• if(isset($_POST['ctext'][$pen['id']])){ $ctext = $_POST['ctext'][$pen['id']]; } uses $pen['id'] to look up the corresponding value in $_POST['ctext'].

By the way, when outputting user input you should always escape it, e.g. with htmlspecialchars. This will look like this: echo htmlspecialchars($ctext); That way malicious input like "><script>alert('Hello!')</script> won't execute the javascript.

Update: as requested a solution using session to store data:

<?php

$connect = mysqli_connect('localhost', 'root', 'root123', 'font');
$query = 'SELECT * FROM pens ORDER by id ASC';
$result = mysqli_query($connect, $query);

if($result):
    if(mysqli_num_rows($result)>0):
        session_start();
        if (isset($_POST['ctext'])) {
            $_SESSION['ctext'][$_POST['id']] = $_POST['ctext'];
        }
        while( $pen = mysqli_fetch_assoc($result) ):
        ?>
        <form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>?action=add&id=<?php echo $pen['id']; ?>">

            <div class="name pen-<?php echo $pen['id']; ?>">
                <input type="text" name="ctext" class="form-control" placeholder="Type your text here" value="<?php $ctext = ''; if(isset($_SESSION['ctext'][$pen['id']])){ $ctext = $_SESSION['ctext'][$pen['id']]; } echo htmlspecialchars($ctext); ?>"></input>
                <input type="hidden" name="id" value="<?php echo $pen['id']?>"></input>
            </div>

            <div class="btn-custom">
                <input type="submit" name="add_to_cart" class="btn btn-block" value="Accept"></input>
            </div>      
        </form>
        <?php
        endwhile;
    endif;
endif;

Note: I removed the now unnecessary counter $i. The session handling is mainly done before the while loop (start a session and store POST data). During output the values from the session are used. The name of the input is not an array anymore.