dongzhi1822 2019-05-30 12:10
浏览 38

使用数据B替换数据A并输出数据B.

The teacher table has elements of teacher's name , position, userid and password. I want to replace the userid with teacher's name in the another table named Subject so that it is easier to refer. So how can I do it using PHP coding ?

<?php
    include ('connection.php');
    $data1 = mysqli_query($connect,"SELECT * FROM teacher");

    while ($info1=mysqli_fetch_array($data1))
    {
        echo "<option hidden selected> -- Your Option -- </option>";
        echo "<option value=$info1[userid]>$info1[name]</option>";  
    }

I expect to have the teacher's name as an option but it came out $info1[name]

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2条回答 默认 最新

  • duan88014 2019-05-30 12:28
    关注

    You just need to do syntax changes as follows:

    while ($info1=mysqli_fetch_array($data1))
    {
        echo "<option hidden selected> -- Your Option -- </option>";
        echo "<option value='$info1[userid]'>'$info1[name]'</option>";  
    }
    

    Because PHP take $info1[name] as a string, you need to use single quote to interpret the variable value.

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