duanliang2017 2017-02-06 06:14
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我在php表单输出上得到了一个非常奇怪的结果

Here is my code:

<h2> Simple Form </h2>
<form action="" method="post">
First Name: <input type="text" name="firstName">
Last Name: <input type="text" name="lastName"><br /><br />
<input type="submit">
</form>
<br />
Welcome,
<?php
echo $_POST['firstName'];
echo " ";
echo $_POST['lastName'];
?>
!
<hr>
<h2>POST Form</h2>
<h3>Would you like to volunteer for our program?</h3>
<form action="" method="post">
Name: <input type="text" name="postName">
Age: <input type="text" name="age"><br /><br />
<input type="submit">
</form>
<br />
Hello,
<?php
echo $_POST['postName'];
?>
!
<br>
<?php
if ($_SERVER['REQUEST_METHOD'] == "POST") {
    $age = $_POST['age'];
    if ($age >= 16) {
        echo "You are old enough to volunteer for our program!";
    } else {
        echo "Sorry, try again when you're 16 or older.";
    }
}
?>
<hr>
<h2>GET Form</h2>
<h3>Would you like to volunteer for our program?</h3>
<form method="get" action="<?php echo htmlspecialchars($_SERVER["REQUEST_URI"]); ?>">
<input type="hidden" name="p" value="includes/forms.php">
Name: <input type="text" name="getName">
Age: <input type="text" name="age"><br /><br />
<input type="submit">
</form>
<br />
Hello,
<?php
echo $_GET['getName'];
?>
!
<br>
<?php
if ($_SERVER['REQUEST_METHOD'] == "GET") {
    $age = $_GET['age'];
    if ($age >= 16) {
        echo "You are old enough to volunteer for our program!";
    } else {
        echo "Sorry, try again when you're 16 or older.";
    }
}
?>

I have two forms. Both displaying the exact same thing, but one form using POST and one using GET.

I have gotten so close to finishing this off but now I have another small/weird issue.

The code technically works correctly, but here's the output explanation:

when I first open up the page the GET form already has the result "Sorry, try again when you're 16 or older." When I fill out the first 'simple' form, it displays the result correctly but then the POST form shows the "Sorry, try again..." result. Then, when I fill in the information and click submit, it displays the correct result and the other two forms are blank as they're supposed to be, and then the same result when I fill out the GET form.

Any help on this is much appreciated.

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3条回答 默认 最新

  • dongwopu8210 2017-02-06 06:30
    关注

    Try this code :

       <h2> Simple Form </h2>
    
       <form action="" method="post">
          First Name: <input type="text" name="firstName">
        Last Name: <input type="text" name="lastName"><br /><br />
         <input type="submit">
     </form>
     <br />
    
      Welcome, 
    
      <?php
         if (isset($_POST['firstName']) && $_POST['lastName'])
        {
       echo $_POST['firstName'];
       echo " ";
       echo $_POST['lastName'];
       }
       ?>
    
       ! 
        <hr>
    
    
     <h2>POST Form</h2>
    
     <h3>Would you like to volunteer for our program?</h3>
    
      <form action="" method="post">
      Name: <input type="text" name="postName">
      Age: <input type="text" name="age"><br /><br />
        <input type="submit">
      </form>
      <br />
    
    
      Hello, 
    
      <?php
      if (isset($_POST['postName']))
      {
       echo $_POST['postName'];
       }
      ?>
    
        !
       <br>
    
    
      <?php
     if ($_SERVER['REQUEST_METHOD'] == "POST")
     {
    
     if (isset($_POST['age']))
     {
        $age = $_POST['age'];
    
        if ($age >= 16)
        {
    
            echo "You are old enough to volunteer for our program!";
        }
        else
        {
            echo "Sorry, try again when you're 16 or older.";
        }
        }
    }
    ?>
    
     <hr>
    
       <h2>GET Form</h2>
    
       <h3>Would you like to volunteer for our program?</h3>
    
      <form method="get" action="<?php echo            htmlspecialchars($_SERVER["REQUEST_URI"]);    ?>"> 
    <input type="hidden" name="p" value="includes/forms.php">
    Name: <input type="text" name="getName">
    Age: <input type="text" name="age"><br /><br />
    <input type="submit">
    </form>
    <br />
    
    Hello, 
    
    <?php
    if (isset($_GET['getName']))
    {
    echo $_GET['getName'];
    }
    ?>
    
    !
    <br>
    
    
    <?php
    if ($_SERVER['REQUEST_METHOD'] == "GET")
    {
    
    
    if (isset($_GET['age']))
    {
        $age = $_GET ['age'];
    
    
    
        if ($age >= 16)
        {
    
            echo "You are old enough to volunteer for our program!";
        }
        else
        {
            echo "Sorry, try again when you're 16 or older.";
        }
    }
    }
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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