PHP preg_match完全匹配并在括号内得到什么

Question

Lets say I have the following string:

"**link(http://google.com)*{Google}**"

And I want to use preg_match to find the EXACT text **link(http://google.com) but the text inside the brackets changes all the time. I used to use:

preg_match('#\((.*?)\)#', $text3, $match2);

Which would get what is inside the brackets which is good but if I had: *hwh(http://google.com)** it would get whats inside of that. So how can i get whats inside the brackets if, in front of the brackets has **link?

Answer 1

~(?:\*\*link\(([^\)]+)\))~ will match contents in the brackets for all inputs that look like **link(URL) but do not contain extra ) inside URLs. See the example on Regexr: http://regexr.com/3en33 . The whole example:

$text = '"**link(http://google.com)*{Google}**"
**link(arduino.cc)*{official Arduino site}';
$regex = '~(?:\*\*link\((?<url>[^)]+))~';
preg_match_all($regex, $text, $matches);

var_dump($regex, $matches['url']);