doucuyu2259 2016-10-23 12:25
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用isset($ _ SESSION)替换不是session_is_registered()?

I was working in a login system session_is_registered but this function doesnt work in php5.4+ so I replaced:

   if (session_is_registered('id_user') == true && session_is_registered ('username') == true){}

to

if (isset($_SESSION['id_user']) && isset($_SESSION['username'])){}

...and it works.

But what happens if a want to replace (becouse I need to use this expression)

if (!session_is_registered('id_user') || !session_is_registered('username')){}

Do I need to use !isset() or empty()?

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1条回答 默认 最新

  • duanposhi3641 2016-10-23 12:45
    关注

    You can use like this way

    if (isset($_SESSION['id_user']) && isset($_SESSION['username'])){
          /* this will true if both are set */
    }
    
    if (!isset($_SESSION['id_user']) || !isset($_SESSION['username'])){
          /* this will true if one of them is not set */
    }
    

    isset will give true if variable is set
    empty will give true if variable is set and its blank or null

    isset() is NOT equivalent to empty().

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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