检测字符串中混淆的脏话

Question

I want a function or method in PHP that will detect swearwords in obscured text. Something that will check string like:

$string = "hey you swearword!" or 
$string = "hey you swear#word!"

or maybe even

$string = "hey you sw3arw0rd!"

for "swearword" and will return true if it contains that bad swearword and false if it does not. I don't want people to use bad word on my site, please help!

Answer 1

Just a simple example to show the direction:

$stopwords = ['swearword'];

$test = ['swear#word','sw3arw0rd','goodword','swearw*rd','swe*rw*rd','swe*!**rd'];

foreach($test as $word){
    foreach($stopwords as $stopword){
        if(levenshtein($stopword,$word)<=2){
            print "levenshtein: '$word' seems to mean $stopword<br/>";
            continue 2;
        }
    }
    if(strlen(preg_replace('#[a-zA-Z]+#','',$word))!==0){#special char found
        print "preg_replace: '$word' seems to have illegal chars<br/>";
        continue;
    }
    print "'$word' seems be NO stopword<br/>";
}