duanbi1888 2016-05-08 10:23
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检查查询是否返回任何信息

I've been working on this for hours, can't seem to figure out why its not working.

All of the tutorials I've looked at showed that this worked fine. The output of num_rows is greater than 1 and yet it still goes inside the if statement.

Also it returns 1 even when it should be 0. Maybe it's a BOOL?

if($test = mysqli_num_rows($result) == 0){
    echo "Username and Email are Available test= $test";
} else {
    echo "Username and Email are TAKEN";
}
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  • dsj8000 2016-05-08 10:26
    关注

    Your statement only evaluates to true if num_rows is equal to one:

    if($test = mysqli_num_rows($result) == 0){
    

    You need to change it to more than equals to 1 or more than 0:

    if(mysqli_num_rows($result) >= 1){
        echo "Username and Email are Available test= $test";
    } else {
        echo "Username and Email are TAKEN";
    }
    

    Usage of mysqli_num_rows():

    Returns the number of rows in the result set.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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