2017-04-05 12:51
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I need get a list of all file url in one of my database field.

mysql database, article table

`id` | `subject` | `content`

the value of content is html text with one or more file url, for example:

<p>this is the answer for ..., you can refer to below screenshot:</p>
<img src="http://the_url_of_image_here/imagename.jpg/>

<p>or refer to below document</p>

<a href="http://the_url_of_doc_here/guide.ppt>guide</a>
<a href="http://the_url_of_doc_here/sample.dox>sample</a>

there are 2 types of files

  1. image,with extension jpg,jpeg,png,bmp,gif
  2. document, with extension doc,docx,ppt,pptx,xls,xlsx,pdf,xps

I did a lot goolge, look like it's hard to do it only with mysql, php would make it easy, I write my codes but it can not work.

Thanks cars10, I solved it.

function export_articles_link()
    global $date_from, $date_to;
    $filename = "kb_articles_link_".$date_from."_".$date_to.".xlsx";
    header('Content-disposition: attachment;        filename="'.XLSXWriter::sanitize_filename($filename).'"');
    header("Content-Type: application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");
    header('Content-Transfer-Encoding: binary');
    header('Cache-Control: must-revalidate');
    header('Pragma: public');
    $query = 'SELECT `content` FROM `kb_articles` WHERE ((DATE(`dt`) BETWEEN \'' . $date_from . '\' AND \'' . $date_to . '\') AND (`content` LIKE \'%<img src=%\' or `content` LIKE \'%<a href="http:%\')) order by id asc';
    $result = mysql_query($query);
    $writer = new XLSXWriter(); 
    $img_list = array();
    while ($row=mysql_fetch_array($result))
        $text = $row['content'];
        preg_match_all('!http://.+\.(?:jpe?g|png|gif|ppt?|xls?|doc?|pdf|xdw)!Ui', $text, $matches);
        $img_list = $matches[0];
        foreach ($img_list as $url)
        $writer->writeSheetRow('Sheet1', array($url)); // if more than one url it will be put on first column

share with others who need a work sample,hope it save your time.

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