2016-08-06 14:57
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PHP,MySQL,HTML / CSS和javascript - 带有模态框弹出窗口的循环和按钮

So I've been breaking my brain over this one and I still can't figure it out. I have only basic knowledge of PHP and Modal Boxes and Javascript. So here's my concern...

I have PHP getting MySQL data from my database and placing this data in a table on my website [Bear in mind, this is a website for a fastfood restaurant]. I have a while loop that runs and adds each record in a table, and I add an ORDER button for each item. Each button is intended to open a modal box with the relevant item's information (so that I can add it to the shopping cart: i do have the shopping cart in order though).

Only the [ORDER] Button of the first item opens a modal box. The other buttons DON'T OPEN UP MODAL BOXES.

$con = mysqli_connect("localhost","root","root","mcd");
    die("Can not connect".mysql_error());
$query = mysqli_query($con, "select * from pizza");
echo "<table border=1 align='center' width=50%>
    while ($record = mysqli_fetch_array($query)) {
        echo "<tr>";
        echo "<td align='right'>".$record['pizzaName']."</td>";
        echo "<td align='right'> R".$record['PriceMedium']."</td>";
        echo "<td align='right'> R".$record['PriceLarge']."</td>";
        echo "<td align='right'> <input id='myBtn' type='button' value='ORDER'/>";
        echo "</tr>";
   echo "</table>";
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1条回答 默认 最新

  • drpph80800
    drpph80800 2016-08-06 20:55

    I believe your problem come from the fact that your input has a id defined but no class.

    As Id are intended to be unique on a page, if you bind a javascript function on elements selected by id, only the first element having this id will be bound.

    I suggest you use


    instead of


    then adapt your javascript part accordingly.

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