使用YIIC Shell将参数传递给命令行

Question

I am trying to pass parameters to command line and get the values using getopt() function. It works fine when I use

    php file.php -a arg

But it does not show any value when I use

    yiic shell file.php -a arg

I think I am using the incorrect syntax but I didn't get any proper result when I googled for the correct answer. Any help will be appreciated. Thanks in advance!

Answer 1

You should use the name of your command instead of the file name. For example, if you have a MyCommandNameCommand class that extends from CConsoleCommand you have to execute the following command from the command line:

    yiic shell mycommandname arg1 arg2 ...

Hope it helps.