Php使用Fopen功能和直播（rtp）

Question

I am trying to prepare a webcam streaming page. I created a vlc streaming and here is what I wrote in the command line to run my webcam.

cvlc -vvv v4l2:///dev/video0 --sout '#transcode{vcodec=mp2v,vb=800,acodec=none}:rtp{dst=239.0.0.1,port=5004,mux=ts}'

After typing this code i can see my webcam by typing

rtp://239.0.0.1:5004/ 

to the browser. Its okay up to here.

I prepared a php streaming file and it opens static video files with

fopen('localhost/sample.mp4','rb') 

command and it works properly. But when I pass "rtp://239.0.0.1:5004"/ in

 fopen( 'rtp://239.0.0.1:5004/', "rb" )

command, I get en error 502 gateway that probably means it has not opened rtp file.

What should I do ? Thanks

Answer 1

PHP can only open resources using some protocols.

file:// — Accessing local filesystem 
http:// — Accessing HTTP(s) URLs  
ftp:// — Accessing FTP(s) URLs
php:// — Accessing various I/O streams
zlib:// — Compression Streams
data:// — Data (RFC 2397) 
glob:// —    Find pathnames matching pattern
phar:// — PHP Archive
ssh2:// —    Secure Shell 2
rar:// — RAR
ogg:// — Audio streams
expect:// —    Process Interaction Streams

As you see rtp is not one of theese. you need to find/write rtp wrapper to reed this resource.