dongyin8009
dongyin8009
2015-08-11 09:59

Php ajax只想显示错误信息表单提交

已采纳

After send my form data to php file its return if any error found. But its also return success before ajax redirect page. I want display error message only and if success, redirect another page.

ajax:

$("#msform").submit(function(){
     $.ajax({
           type:"post",
           url:"pagesubmit.php",
           data:  $("#msform").serialize(),
           dataType : 'json',
           success: function(data){
           if ( ! data.success) {
                $(".help-block").fadeIn().html(data.error);
           } else {
                $(".help-block").fadeOut();
                $("#msform")[0].reset();
                window.location = 'http://dbsvawdez.com/' + data.success;
           }
           }
     });
});

php:

include_once ("db.php");
global $dbh;

function check($name){
  if(!$name || strlen($name = trim($name)) == 0){
     $error ="* Username not entered";
  }
  else{
     $name = stripslashes($name);
     if(strlen($name) < 5){
        $error ="* Name below 5 characters";
     }
     else if(!preg_match("/^([0-9a-z])+$/i", $name)){
        $error ="* Name not alphanumeric";
     }
     else {
        return 1;  
     }
  } 
}

  $name = mysqli_real_escape_string($dbh, $_POST['name']);

  $thisname = strtolower($name);

  $retval = check($thisname);

  if($retval ==1){ // if no error found
   $success ='upage/userpage?user='.$_SESSION['username'].'';                           
  }


$data = array();
$data['error'] = $error;
$data['success'] = $success;
if (!empty($data)) {
    echo json_encode($data);
}
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2条回答

  • dousu8767 dousu8767 6年前

    Solved the problem, in this way:

    Ajax:

    $("#msform").submit(function(){
    // collect input name
    ver name = var catag=$('#name').val();
       $.ajax({
           type:"post",
           url:"pagesubmit.php",
           data:  $("#msform").serialize(),
           success: function(data){
           if ( data != 'success') {
                $(".help-block").fadeIn().html(data);
           } else {
                $(".help-block").fadeOut();
                $("#msform")[0].reset();
                window.location = 'http://dbsvawdez.com/' + name;
           }
           }
       });
    });
    

    php:

    function check($name){
        if(!$name || strlen($name = trim($name)) == 0){
        echo "* Username not entered";
        }
        else{
            $name = stripslashes($name);
            if(strlen($name) < 5){
            echo "* Name below 5 characters";
            }
            else if(!preg_match("/^([0-9a-z])+$/i", $name)){
            echo "* Name not alphanumeric";
            }
            else {
            return 1;  
            }
        } 
    }
    
    $name = mysqli_real_escape_string($dbh, $_POST['name']);
    $thisname = strtolower($name);
    $retval = check($thisname);
    if($retval ==1){ // if no error found
       echo 'success';                         
    }
    
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  • dpylt7626401 dpylt7626401 6年前

    EDIT

    Set your variables $success and $error

    $success = "";
    $error= "";
    

    If you doesn't init them, you cannot use them and the .=operator is for concatenation not for set.

    Then you should encode the response in php in JSON.

    Something like

    $response = json_encode(
        array(  
            'success'=> true,  
            'route' => "mypage/info?user=$_SESSION['username']"
        )
    );
    

    And return this, then access your response like you already do :

    var success = response.success;
    

    UPDATE

    change this code to add an else statement :

    if($retval ==1){ // if no error found
        $success ='upage/userpage?user='.$_SESSION['username'].'';                           
    }else{
        $success = 'error';
    }
    

    and this line :

    else {
        return 1;  
    }
    

    to :

    else {
       $error = 'none';
    }
    

    and in your javascript :

    $("#msform").submit(function(){
        $.ajax({
            type     :"post",
            url      :"pagesubmit.php",
            data     :  $("#msform").serialize(),
            dataType : 'json',
            success  : function(data){
                if(data.success == 'error') {
                    $(".help-block").fadeIn().html(data.error);
                }else{
                    $(".help-block").fadeOut();
                    $("#msform")[0].reset();
                    window.location = 'http://dbsvawdez.com/' + data.success;
                }
            }
        });
    });
    
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