douyi0219 2015-07-15 10:46
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Mysql内连接在另一个表中的值

This is probably a very simple solution but i cannot get my head around the syntax.

I have my first table:

ratings

id
name
status

I then have another table

sectors

id
ratingid
name

So my basic query is SELECT * FROM ratings but what I need to do is select all records from ratings WHERE I then look at the sectors table WHERE the sectorid is passed from $_GET and only show records where the sectorid matches the $_GET

Does that make sense? Any help very appreciated..

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  • dth8312 2015-07-15 10:49
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     SELECT * FROM sectors INNER JOIN ratings
     ON sectors.rating_id = ratings.id
     WHERE sectors.id = $_GET['yoursectorid'];
    

    I think this is what you're looking.

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