dongrong8972 2015-07-08 08:36
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没有从php中的ajax请求收到响应

I have a page where there is table and each row has a icon for detailed information. When the icon is clicked, I get the unique identifier for that row into datastring and send a AJAX request. I get a response but cannot catch the correct response. Why is that I am doing wrong? I need to access the $desc in home.php , how to catch that in response ?

home.php

$.ajax({
        type: "POST",
        url: "actionone.php",
        data: dataString,
        cache: true,  
        success:function() {
        alert("success"); 
    }
});

actionone.php

if(isset($_POST['content']))
{
$content=(int)$_POST['content'];
$fetch = mysql_query("SELECT ISSUEDESCRIPTION FROM issues WHERE KBID =$content");
while($rowe = mysql_fetch_array($fetch))    
{   
    $desc = $rowe['ISSUEDESCRIPTION'];
} 
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1条回答 默认 最新

  • dongyue8640 2015-07-08 08:40
    关注

    For ajax success work you output some from php code ie Change php code to

    if(isset($_POST['content']))
    {
        $content=(int)$_POST['content'];
        $fetch = mysql_query("SELECT ISSUEDESCRIPTION FROM issues WHERE KBID =$content");
        while($rowe = mysql_fetch_array($fetch))    
        {   
             $desc = $rowe['ISSUEDESCRIPTION'];
        }
        echo $desc;
    }
    

    JQUERY

    $.ajax({
            type: "POST",
            url: "actionone.php",
            data: dataString,
            cache: true,  
            success:function(data) {
            alert(data.trim()); 
        }
    });
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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