dongluojiao6322 2019-01-14 12:10
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Ajax请求从PHP获得不同的响应值

I have this ajax request code

$("#input_form").on("your change event",function(e){
        if(changeTimer !== false) clearTimeout(changeTimer);
        changeTimer = setTimeout(function(){
    $.ajax({
        type: 'POST',
        url: 'exchanger',
        data: $('#depo').serialize(), 
        beforeSend: function() {
            $("#result").addClass('deposit-input-loading');
        }
    }).done(function(t) {
        data = $.parseJSON(t);
        setTimeout(function() {
            $("#result").removeClass('deposit-input-loading');
            $("#ex_limit").html('min: '+data.value);
            $("#received_amount").val(data.receive_amount);
        }, 1000);
    })
            changeTimer = false;
        },50);
});

But error in after done function in ajax request. my PHP file code was like this

$rate = $API->getRate($send, $received, $amount);
$limits = $API->getLimits($send, $received);
echo json_encode($rate);
echo json_encode($limits);

the echo json_encode show different array How to get the response from different json_encode and show in ajax request?

  • 写回答

1条回答 默认 最新

  • duanci6484 2019-01-14 13:11
    关注

    Try this into your PHP File:

    $rate = $API->getRate($send, $received, $amount);
    $limits = $API->getLimits($send, $received);
    $array = array('rate' => $rate, 'limits' => $limits); 
    echo json_encode($array); exit; 
    

    Then check your data variable in ajax done method.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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