dougai3418 2015-07-08 10:33
浏览 62

在php中重新加载页面后,在下拉列表中保留选定的值

I have a dropdown in my form, In which data is being fetch from database, Problem is i want to keep the selected value in the dropdown if page reloads. Any help will be really appreciated.

Here is my code

 <select name="ans_type" class="select-form " onChange="checkAnswer(this.value)"             style="background-color: #fff !important;width:159px!important;">
        <option value="" style="color:#000">Select</option>
        <?php
        $sql = "select * from (table name)";
        $res = mysqli_query($dbhandle,$sql);
        $numrows = mysqli_num_rows($res);
        if($numrows){
            while($obj = mysqli_fetch_object($res)){
                if($ansTypeId == $obj->id){
                    echo '<option value="'.$obj->id.'" style="color:#000" selected>'.($obj->ans_type).'</option>';
                }
                else{
                    echo '<option value="'.$obj->id.'" style="color:#000">'.($obj->ans_type).'</option>';
                }   
            }   
        }
        ?>
</select>
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2条回答 默认 最新

  • doumengyin0491 2015-07-08 10:47
    关注

    Try this

    selected = '';
          if($ansTypeId == $obj->id){
                          $selected = "selected='selected'"; 
          }
    echo '<option value="'.$obj->id.'" style="color:#000" $selected>'.
    ($obj->ans_type).'</option>';
    
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